164025131 has 16 divisors (see below), whose sum is σ = 173534400. Its totient is φ = 154818048.

The previous prime is 164025101. The next prime is 164025137. The reversal of 164025131 is 131520461.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-164025131 is a prime.

It is a super-2 number, since 2×164025131² = 53808487199134322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 164025097 and 164025106.

It is not an unprimeable number, because it can be changed into a prime (164025137) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 265535 + ... + 266151.

It is an arithmetic number, because the mean of its divisors is an integer number (10845900).

Almost surely, 2^164025131 is an apocalyptic number.

164025131 is a deficient number, since it is larger than the sum of its proper divisors (9509269).

164025131 is a wasteful number, since it uses less digits than its factorization.

164025131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 838.

The product of its (nonzero) digits is 720, while the sum is 23.

The square root of 164025131 is about 12807.2296379818. The cubic root of 164025131 is about 547.3983253297.

Adding to 164025131 its reverse (131520461), we get a palindrome (295545592).

The spelling of 164025131 in words is "one hundred sixty-four million, twenty-five thousand, one hundred thirty-one".