Base | Representation |
---|---|
bin | 1110111011110011010100… |
… | …1000101001110101010011 |
3 | 2011010210022110111011121011 |
4 | 3232330311020221311103 |
5 | 4123013242131333210 |
6 | 54531255220511351 |
7 | 3313226400145423 |
oct | 356746510516523 |
9 | 64123273434534 |
10 | 16420551433555 |
11 | 5260a0a223aa5 |
12 | 1a124b554b557 |
13 | 9215b3824109 |
14 | 40aa8a70a483 |
15 | 1d7209b67d8a |
hex | eef35229d53 |
16420551433555 has 8 divisors (see below), whose sum is σ = 19704799440144. Its totient is φ = 13136349333600.
The previous prime is 16420551433487. The next prime is 16420551433651. The reversal of 16420551433555 is 55533415502461.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 16420551433555 - 223 = 16420543044947 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 16420551433499 and 16420551433508.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10684761 + ... + 12124570.
It is an arithmetic number, because the mean of its divisors is an integer number (2463099930018).
Almost surely, 216420551433555 is an apocalyptic number.
16420551433555 is a deficient number, since it is larger than the sum of its proper divisors (3284248006589).
16420551433555 is a wasteful number, since it uses less digits than its factorization.
16420551433555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22953317.
The product of its (nonzero) digits is 5400000, while the sum is 49.
The spelling of 16420551433555 in words is "sixteen trillion, four hundred twenty billion, five hundred fifty-one million, four hundred thirty-three thousand, five hundred fifty-five".
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