Base | Representation |
---|---|
bin | 11110100101111011… |
… | …11001001110000001 |
3 | 1120101122022001010211 |
4 | 33102331321032001 |
5 | 232114112424101 |
6 | 11313434354121 |
7 | 1121003415115 |
oct | 172275711601 |
9 | 46348261124 |
10 | 16424342401 |
11 | 6a691275a5 |
12 | 322458b941 |
13 | 171996b5cc |
14 | b1b471745 |
15 | 661db6c51 |
hex | 3d2f79381 |
16424342401 has 4 divisors (see below), whose sum is σ = 16424966592. Its totient is φ = 16423718212.
The previous prime is 16424342383. The next prime is 16424342411. The reversal of 16424342401 is 10424342461.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 16424342401 - 211 = 16424340353 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (16424342411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 270805 + ... + 325858.
It is an arithmetic number, because the mean of its divisors is an integer number (4106241648).
Almost surely, 216424342401 is an apocalyptic number.
It is an amenable number.
16424342401 is a deficient number, since it is larger than the sum of its proper divisors (624191).
16424342401 is an equidigital number, since it uses as much as digits as its factorization.
16424342401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 624190.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 16424342401 its reverse (10424342461), we get a palindrome (26848684862).
The spelling of 16424342401 in words is "sixteen billion, four hundred twenty-four million, three hundred forty-two thousand, four hundred one".
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