16441325531 has 4 divisors (see below), whose sum is σ = 16441713912. Its totient is φ = 16440937152.

The previous prime is 16441325521. The next prime is 16441325567. The reversal of 16441325531 is 13552314461.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13552314461 = 7 ⋅1936044923.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-16441325531 is a prime.

It is a super-3 number, since 3×16441325531³ (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 16441325491 and 16441325500.

It is not an unprimeable number, because it can be changed into a prime (16441325521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121661 + ... + 218366.

It is an arithmetic number, because the mean of its divisors is an integer number (4110428478).

Almost surely, 2^16441325531 is an apocalyptic number.

16441325531 is a deficient number, since it is larger than the sum of its proper divisors (388381).

16441325531 is an equidigital number, since it uses as much as digits as its factorization.

16441325531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 388380.

The product of its digits is 43200, while the sum is 35.

Adding to 16441325531 its reverse (13552314461), we get a palindrome (29993639992).

The spelling of 16441325531 in words is "sixteen billion, four hundred forty-one million, three hundred twenty-five thousand, five hundred thirty-one".