16442664002017 has 4 divisors (see below), whose sum is σ = 17937451638576. Its totient is φ = 14947876365460.

The previous prime is 16442664001979. The next prime is 16442664002021. The reversal of 16442664002017 is 71020046624461.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 16442664002017 - 2³¹ = 16440516518369 is a prime.

It is a super-3 number, since 3×16442664002017³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (16442664002077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 747393818263 + ... + 747393818284.

It is an arithmetic number, because the mean of its divisors is an integer number (4484362909644).

Almost surely, 2^{16442664002017} is an apocalyptic number.

It is an amenable number.

16442664002017 is a deficient number, since it is larger than the sum of its proper divisors (1494787636559).

16442664002017 is a wasteful number, since it uses less digits than its factorization.

16442664002017 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1494787636558.

The product of its (nonzero) digits is 387072, while the sum is 43.

The spelling of 16442664002017 in words is "sixteen trillion, four hundred forty-two billion, six hundred sixty-four million, two thousand, seventeen".