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16464714055507 = 84551194731157
BaseRepresentation
bin1110111110010111110101…
…1011101011111101010011
32011022000022020020210221001
43233211331123223331103
54124224213244234012
655003441335042431
73316351651222324
oct357457533537523
964260266223831
1016464714055507
115278711939573
121a1ab7b510417
139258010c6093
1440cc79a8044b
151d8441ce9357
hexef97d6ebf53

16464714055507 has 4 divisors (see below), whose sum is σ = 16464908871216. Its totient is φ = 16464519239800.

The previous prime is 16464714055499. The next prime is 16464714055577. The reversal of 16464714055507 is 70555041746461.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 16464714055507 - 23 = 16464714055499 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (16464714055577) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97281028 + ... + 97450129.

It is an arithmetic number, because the mean of its divisors is an integer number (4116227217804).

Almost surely, 216464714055507 is an apocalyptic number.

16464714055507 is a deficient number, since it is larger than the sum of its proper divisors (194815709).

16464714055507 is an equidigital number, since it uses as much as digits as its factorization.

16464714055507 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 194815708.

The product of its (nonzero) digits is 14112000, while the sum is 55.

The spelling of 16464714055507 in words is "sixteen trillion, four hundred sixty-four billion, seven hundred fourteen million, fifty-five thousand, five hundred seven".

Divisors: 1 84551 194731157 16464714055507