Base | Representation |
---|---|
bin | 1110111110110101101011… |
… | …1111110111010010001001 |
3 | 2011022202222121122112111012 |
4 | 3233231122333313102021 |
5 | 4124342120411133423 |
6 | 55011244352413305 |
7 | 3320054341020440 |
oct | 357553277672211 |
9 | 64282877575435 |
10 | 16472726271113 |
11 | 528105359a762 |
12 | 1a20636847235 |
13 | 9264aa025368 |
14 | 40d3d9c07d57 |
15 | 1d8760409078 |
hex | efb5aff7489 |
16472726271113 has 8 divisors (see below), whose sum is σ = 18826004038080. Its totient is φ = 14119456293360.
The previous prime is 16472726271097. The next prime is 16472726271121. The reversal of 16472726271113 is 31117262727461.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 16472726271113 - 24 = 16472726271097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (16472726271193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3661418 + ... + 6808188.
It is an arithmetic number, because the mean of its divisors is an integer number (2353250504760).
Almost surely, 216472726271113 is an apocalyptic number.
It is an amenable number.
16472726271113 is a deficient number, since it is larger than the sum of its proper divisors (2353277766967).
16472726271113 is an equidigital number, since it uses as much as digits as its factorization.
16472726271113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3894607.
The product of its digits is 1185408, while the sum is 50.
Adding to 16472726271113 its reverse (31117262727461), we get a palindrome (47589988998574).
The spelling of 16472726271113 in words is "sixteen trillion, four hundred seventy-two billion, seven hundred twenty-six million, two hundred seventy-one thousand, one hundred thirteen".
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