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16490226635473 = 46135770556693
BaseRepresentation
bin1110111111110110111000…
…0110011101001011010001
32011101110011020200011021011
43233331232012131023101
54130133441004313343
655023301110130521
73321244121454043
oct357755606351321
964343136604234
1016490226635473
1152885140444a8
121a23abb650a41
1392803889a646
144101ba135a93
151d8e369bc29d
hexeff6e19d2d1

16490226635473 has 4 divisors (see below), whose sum is σ = 16525997192628. Its totient is φ = 16454456078320.

The previous prime is 16490226635453. The next prime is 16490226635543. The reversal of 16490226635473 is 37453662209461.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1909528768449 + 14580697867024 = 1381857^2 + 3818468^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-16490226635473 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (16490226635453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17885277886 + ... + 17885278807.

It is an arithmetic number, because the mean of its divisors is an integer number (4131499298157).

Almost surely, 216490226635473 is an apocalyptic number.

It is an amenable number.

16490226635473 is a deficient number, since it is larger than the sum of its proper divisors (35770557155).

16490226635473 is an equidigital number, since it uses as much as digits as its factorization.

16490226635473 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35770557154.

The product of its (nonzero) digits is 39191040, while the sum is 58.

The spelling of 16490226635473 in words is "sixteen trillion, four hundred ninety billion, two hundred twenty-six million, six hundred thirty-five thousand, four hundred seventy-three".

Divisors: 1 461 35770556693 16490226635473