164914093131 has 4 divisors (see below), whose sum is σ = 219885457512. Its totient is φ = 109942728752.

The previous prime is 164914093093. The next prime is 164914093133. The reversal of 164914093131 is 131390419461.

164914093131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 164914093131 - 2¹⁸ = 164913830987 is a prime.

It is a super-2 number, since 2×164914093131² (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (164914093133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27485682186 + ... + 27485682191.

It is an arithmetic number, because the mean of its divisors is an integer number (54971364378).

Almost surely, 2^164914093131 is an apocalyptic number.

164914093131 is a deficient number, since it is larger than the sum of its proper divisors (54971364381).

164914093131 is an equidigital number, since it uses as much as digits as its factorization.

164914093131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54971364380.

The product of its (nonzero) digits is 69984, while the sum is 42.

The spelling of 164914093131 in words is "one hundred sixty-four billion, nine hundred fourteen million, ninety-three thousand, one hundred thirty-one".