165034105128393 has 4 divisors (see below), whose sum is σ = 220045473504528. Its totient is φ = 110022736752260.

The previous prime is 165034105128391. The next prime is 165034105128397. The reversal of 165034105128393 is 393821501430561.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 165034105128393 - 2¹ = 165034105128391 is a prime.

It is a super-3 number, since 3×165034105128393³ (a number of 44 digits) contains 333 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (165034105128391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27505684188063 + ... + 27505684188068.

It is an arithmetic number, because the mean of its divisors is an integer number (55011368376132).

Almost surely, 2^{165034105128393} is an apocalyptic number.

It is an amenable number.

165034105128393 is a deficient number, since it is larger than the sum of its proper divisors (55011368376135).

165034105128393 is an equidigital number, since it uses as much as digits as its factorization.

165034105128393 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55011368376134.

The product of its (nonzero) digits is 2332800, while the sum is 51.

The spelling of 165034105128393 in words is "one hundred sixty-five trillion, thirty-four billion, one hundred five million, one hundred twenty-eight thousand, three hundred ninety-three".