16655130263553 has 4 divisors (see below), whose sum is σ = 22206840351408. Its totient is φ = 11103420175700.

The previous prime is 16655130263423. The next prime is 16655130263579. The reversal of 16655130263553 is 35536203155661.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 16655130263553 - 2⁸ = 16655130263297 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 16655130263496 and 16655130263505.

It is not an unprimeable number, because it can be changed into a prime (16655130263753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2775855043923 + ... + 2775855043928.

It is an arithmetic number, because the mean of its divisors is an integer number (5551710087852).

Almost surely, 2^{16655130263553} is an apocalyptic number.

It is an amenable number.

16655130263553 is a deficient number, since it is larger than the sum of its proper divisors (5551710087855).

16655130263553 is an equidigital number, since it uses as much as digits as its factorization.

16655130263553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5551710087854.

The product of its (nonzero) digits is 7290000, while the sum is 51.

The spelling of 16655130263553 in words is "sixteen trillion, six hundred fifty-five billion, one hundred thirty million, two hundred sixty-three thousand, five hundred fifty-three".