Base | Representation |
---|---|
bin | 1001101100101110110… |
… | …0101010101001011001 |
3 | 120221002110200001222110 |
4 | 2123023230222221121 |
5 | 10212222304203423 |
6 | 204314054342533 |
7 | 15016103452263 |
oct | 2331354525131 |
9 | 527073601873 |
10 | 166626241113 |
11 | 64736195192 |
12 | 2836295aa49 |
13 | 12935cbb357 |
14 | 80c997ab33 |
15 | 4503578193 |
hex | 26cbb2aa59 |
166626241113 has 4 divisors (see below), whose sum is σ = 222168321488. Its totient is φ = 111084160740.
The previous prime is 166626241057. The next prime is 166626241121. The reversal of 166626241113 is 311142626661.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 166626241113 - 210 = 166626240089 is a prime.
It is a super-2 number, since 2×1666262411132 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (166626241213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27771040183 + ... + 27771040188.
It is an arithmetic number, because the mean of its divisors is an integer number (55542080372).
Almost surely, 2166626241113 is an apocalyptic number.
It is an amenable number.
166626241113 is a deficient number, since it is larger than the sum of its proper divisors (55542080375).
166626241113 is an equidigital number, since it uses as much as digits as its factorization.
166626241113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55542080374.
The product of its digits is 62208, while the sum is 39.
Adding to 166626241113 its reverse (311142626661), we get a palindrome (477768867774).
The spelling of 166626241113 in words is "one hundred sixty-six billion, six hundred twenty-six million, two hundred forty-one thousand, one hundred thirteen".
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