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1678134092545 = 5335626818509
BaseRepresentation
bin11000011010111000100…
…101100010001100000001
312221102120001100122010201
4120122320211202030001
5204443304311430140
63322531341325201
7232145504301151
oct30327045421401
95842501318121
101678134092545
11597768a45699
12231297866801
13c232a602cb1
145b317714761
152d9bad7b49a
hex186b8962301

1678134092545 has 4 divisors (see below), whose sum is σ = 2013760911060. Its totient is φ = 1342507274032.

The previous prime is 1678134092507. The next prime is 1678134092561. The reversal of 1678134092545 is 5452904318761.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 443075278321 + 1235058814224 = 665639^2 + 1111332^2 .

It is a cyclic number.

It is not a de Polignac number, because 1678134092545 - 211 = 1678134090497 is a prime.

It is a super-2 number, since 2×16781340925452 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 167813409250 + ... + 167813409259.

It is an arithmetic number, because the mean of its divisors is an integer number (503440227765).

It is a 1-persistent number, because it is pandigital, but 2⋅1678134092545 = 3356268185090 is not.

Almost surely, 21678134092545 is an apocalyptic number.

It is an amenable number.

1678134092545 is a deficient number, since it is larger than the sum of its proper divisors (335626818515).

1678134092545 is an equidigital number, since it uses as much as digits as its factorization.

1678134092545 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 335626818514.

The product of its (nonzero) digits is 7257600, while the sum is 55.

The spelling of 1678134092545 in words is "one trillion, six hundred seventy-eight billion, one hundred thirty-four million, ninety-two thousand, five hundred forty-five".

Divisors: 1 5 335626818509 1678134092545