Base | Representation |
---|---|
bin | 11111010011000100… |
… | …01111001001010011 |
3 | 1121101000202020000121 |
4 | 33221202033021103 |
5 | 233403024440042 |
6 | 11415201531111 |
7 | 1133251605220 |
oct | 175142171123 |
9 | 47330666017 |
10 | 16802968147 |
11 | 7142923739 |
12 | 330b343a97 |
13 | 177a238104 |
14 | b55870947 |
15 | 685257367 |
hex | 3e988f253 |
16802968147 has 16 divisors (see below), whose sum is σ = 20356157952. Its totient is φ = 13539899520.
The previous prime is 16802968111. The next prime is 16802968177. The reversal of 16802968147 is 74186920861.
It is not a de Polignac number, because 16802968147 - 219 = 16802443859 is a prime.
It is a super-2 number, since 2×168029681472 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 16802968094 and 16802968103.
It is not an unprimeable number, because it can be changed into a prime (16802968177) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25122 + ... + 185032.
It is an arithmetic number, because the mean of its divisors is an integer number (1272259872).
Almost surely, 216802968147 is an apocalyptic number.
16802968147 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
16802968147 is a deficient number, since it is larger than the sum of its proper divisors (3553189805).
16802968147 is a wasteful number, since it uses less digits than its factorization.
16802968147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 160818.
The product of its (nonzero) digits is 1161216, while the sum is 52.
The spelling of 16802968147 in words is "sixteen billion, eight hundred two million, nine hundred sixty-eight thousand, one hundred forty-seven".
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