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1680549142681 = 2775776054353
BaseRepresentation
bin11000011101001000100…
…010001110000010011001
312221122210100200220010001
4120131020202032002121
5210013231040031211
63324011132253001
7232262401006513
oct30351042160231
95848710626101
101680549142681
115987981a75a2
12231850611161
13c2623a5b046
145b4a6370bb3
152daacdc6ac1
hex1874888e099

1680549142681 has 4 divisors (see below), whose sum is σ = 1680555474612. Its totient is φ = 1680542810752.

The previous prime is 1680549142651. The next prime is 1680549142703. The reversal of 1680549142681 is 1862419450861.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 870712934400 + 809836208281 = 933120^2 + 899909^2 .

It is a cyclic number.

It is not a de Polignac number, because 1680549142681 - 215 = 1680549109913 is a prime.

It is a super-2 number, since 2×16805491426812 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1680549142651) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2749600 + ... + 3304753.

It is an arithmetic number, because the mean of its divisors is an integer number (420138868653).

Almost surely, 21680549142681 is an apocalyptic number.

It is an amenable number.

1680549142681 is a deficient number, since it is larger than the sum of its proper divisors (6331931).

1680549142681 is an equidigital number, since it uses as much as digits as its factorization.

1680549142681 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6331930.

The product of its (nonzero) digits is 3317760, while the sum is 55.

The spelling of 1680549142681 in words is "one trillion, six hundred eighty billion, five hundred forty-nine million, one hundred forty-two thousand, six hundred eighty-one".

Divisors: 1 277577 6054353 1680549142681