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1690094433 = 3563364811
BaseRepresentation
bin110010010111100…
…1100101101100001
311100210012200201010
41210233030231201
511430131010213
6435412331133
756611365006
oct14457145541
94323180633
101690094433
11798017a65
123b2013aa9
1320c1bb9a1
141206678ad
159d598ac3
hex64bccb61

1690094433 has 4 divisors (see below), whose sum is σ = 2253459248. Its totient is φ = 1126729620.

The previous prime is 1690094431. The next prime is 1690094447. The reversal of 1690094433 is 3344900961.

1690094433 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1690094433 - 21 = 1690094431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1690094391 and 1690094400.

It is not an unprimeable number, because it can be changed into a prime (1690094431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 281682403 + ... + 281682408.

It is an arithmetic number, because the mean of its divisors is an integer number (563364812).

Almost surely, 21690094433 is an apocalyptic number.

It is an amenable number.

1690094433 is a deficient number, since it is larger than the sum of its proper divisors (563364815).

1690094433 is an equidigital number, since it uses as much as digits as its factorization.

1690094433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 563364814.

The product of its (nonzero) digits is 69984, while the sum is 39.

The square root of 1690094433 is about 41110.7581175536. The cubic root of 1690094433 is about 1191.1606107349.

The spelling of 1690094433 in words is "one billion, six hundred ninety million, ninety-four thousand, four hundred thirty-three".

Divisors: 1 3 563364811 1690094433