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1690237035331 = 13130018233487
BaseRepresentation
bin11000100110001001111…
…110100110001101000011
312222120210112011211102221
4120212021332212031003
5210143101140112311
63332252325351511
7233054435514505
oct30461176461503
95876715154387
101690237035331
115a1909818749
122336b4b68597
13c3508b9b8c0
145bb44c8bd75
152de78683671
hex18989fa6343

1690237035331 has 4 divisors (see below), whose sum is σ = 1820255268832. Its totient is φ = 1560218801832.

The previous prime is 1690237035281. The next prime is 1690237035341. The reversal of 1690237035331 is 1335307320961.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1690237035331 - 231 = 1688089551683 is a prime.

It is a super-2 number, since 2×16902370353312 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1690237035341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65009116731 + ... + 65009116756.

It is an arithmetic number, because the mean of its divisors is an integer number (455063817208).

Almost surely, 21690237035331 is an apocalyptic number.

1690237035331 is a deficient number, since it is larger than the sum of its proper divisors (130018233501).

1690237035331 is a wasteful number, since it uses less digits than its factorization.

1690237035331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 130018233500.

The product of its (nonzero) digits is 306180, while the sum is 43.

The spelling of 1690237035331 in words is "one trillion, six hundred ninety billion, two hundred thirty-seven million, thirty-five thousand, three hundred thirty-one".

Divisors: 1 13 130018233487 1690237035331