Base | Representation |
---|---|
bin | 11000100111001010101… |
… | …001110111011101000001 |
3 | 12222200121010221211210001 |
4 | 120213022221313131001 |
5 | 210202311430320001 |
6 | 3332552130440001 |
7 | 233123352546613 |
oct | 30471251673501 |
9 | 5880533854701 |
10 | 1691322120001 |
11 | 5a2316275938 |
12 | 233958433001 |
13 | c364c929637 |
14 | 5bc09026db3 |
15 | 2dedda70001 |
hex | 189caa77741 |
1691322120001 has 4 divisors (see below), whose sum is σ = 1696760455104. Its totient is φ = 1685883784900.
The previous prime is 1691322119983. The next prime is 1691322120011. The reversal of 1691322120001 is 1000212231961.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1691322120001 - 25 = 1691322119969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1691322120011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2719167085 + ... + 2719167706.
It is an arithmetic number, because the mean of its divisors is an integer number (424190113776).
Almost surely, 21691322120001 is an apocalyptic number.
It is an amenable number.
1691322120001 is a deficient number, since it is larger than the sum of its proper divisors (5438335103).
1691322120001 is an equidigital number, since it uses as much as digits as its factorization.
1691322120001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5438335102.
The product of its (nonzero) digits is 1296, while the sum is 28.
Adding to 1691322120001 its reverse (1000212231961), we get a palindrome (2691534351962).
The spelling of 1691322120001 in words is "one trillion, six hundred ninety-one billion, three hundred twenty-two million, one hundred twenty thousand, one".
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