Base | Representation |
---|---|
bin | 11111100110111100… |
… | …11011101110001001 |
3 | 1121210122120021102221 |
4 | 33303132123232021 |
5 | 234223223240431 |
6 | 11443520254041 |
7 | 1140345303043 |
oct | 176336335611 |
9 | 47718507387 |
10 | 16969743241 |
11 | 7218a832a0 |
12 | 3357171321 |
13 | 17a595b5b9 |
14 | b6da84a93 |
15 | 694bec111 |
hex | 3f379bb89 |
16969743241 has 4 divisors (see below), whose sum is σ = 18512447184. Its totient is φ = 15427039300.
The previous prime is 16969743227. The next prime is 16969743319. The reversal of 16969743241 is 14234796961.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 16969743241 - 25 = 16969743209 is a prime.
It is not an unprimeable number, because it can be changed into a prime (16969743341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 771351955 + ... + 771351976.
It is an arithmetic number, because the mean of its divisors is an integer number (4628111796).
Almost surely, 216969743241 is an apocalyptic number.
16969743241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
16969743241 is a deficient number, since it is larger than the sum of its proper divisors (1542703943).
16969743241 is a wasteful number, since it uses less digits than its factorization.
16969743241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1542703942.
The product of its digits is 1959552, while the sum is 52.
The spelling of 16969743241 in words is "sixteen billion, nine hundred sixty-nine million, seven hundred forty-three thousand, two hundred forty-one".
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