Base | Representation |
---|---|
bin | 11111101000011110… |
… | …11001101110100011 |
3 | 1121211112201110100022 |
4 | 33310033121232203 |
5 | 234240020031011 |
6 | 11445055344055 |
7 | 1140562356266 |
oct | 176417315643 |
9 | 47745643308 |
10 | 16982580131 |
11 | 72252508a0 |
12 | 335b52202b |
13 | 17a85044aa |
14 | b71666cdd |
15 | 695dd58db |
hex | 3f43d9ba3 |
16982580131 has 4 divisors (see below), whose sum is σ = 18526451064. Its totient is φ = 15438709200.
The previous prime is 16982580103. The next prime is 16982580163. The reversal of 16982580131 is 13108528961.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13108528961 = 11 ⋅1191684451.
It is a cyclic number.
It is not a de Polignac number, because 16982580131 - 218 = 16982317987 is a prime.
It is a super-3 number, since 3×169825801313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (16982580031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 771935450 + ... + 771935471.
It is an arithmetic number, because the mean of its divisors is an integer number (4631612766).
Almost surely, 216982580131 is an apocalyptic number.
16982580131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
16982580131 is a deficient number, since it is larger than the sum of its proper divisors (1543870933).
16982580131 is a wasteful number, since it uses less digits than its factorization.
16982580131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1543870932.
The product of its (nonzero) digits is 103680, while the sum is 44.
The spelling of 16982580131 in words is "sixteen billion, nine hundred eighty-two million, five hundred eighty thousand, one hundred thirty-one".
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