170113 has 4 divisors (see below), whose sum is σ = 172720. Its totient is φ = 167508.

The previous prime is 170111. The next prime is 170123. The reversal of 170113 is 311071.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311071 = 277 ⋅1123.

It is a cyclic number.

It is not a de Polignac number, because 170113 - 2¹ = 170111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 170093 and 170102.

It is not an unprimeable number, because it can be changed into a prime (170111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1203 + ... + 1336.

It is an arithmetic number, because the mean of its divisors is an integer number (43180).

2¹⁷⁰¹¹³ is an apocalyptic number.

It is an amenable number.

170113 is a deficient number, since it is larger than the sum of its proper divisors (2607).

170113 is an equidigital number, since it uses as much as digits as its factorization.

170113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2606.

The product of its (nonzero) digits is 21, while the sum is 13.

The square root of 170113 is about 412.4475724259. The cubic root of 170113 is about 55.4088539937.

Adding to 170113 its reverse (311071), we get a palindrome (481184).

The spelling of 170113 in words is "one hundred seventy thousand, one hundred thirteen".