Base | Representation |
---|---|
bin | 10000001001101100… |
… | …000011011100001001 |
3 | 1122202121210211122001 |
4 | 100021230003130021 |
5 | 241004124200203 |
6 | 11544512031001 |
7 | 1152522034354 |
oct | 201154033411 |
9 | 48677724561 |
10 | 17342412553 |
11 | 739a381264 |
12 | 343bb32461 |
13 | 1834c20b9b |
14 | ba737329b |
15 | 6b77b291d |
hex | 409b03709 |
17342412553 has 4 divisors (see below), whose sum is σ = 17901845248. Its totient is φ = 16782979860.
The previous prime is 17342412541. The next prime is 17342412557. The reversal of 17342412553 is 35521424371.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 17342412553 - 225 = 17308858121 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (17342412557) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 279716301 + ... + 279716362.
It is an arithmetic number, because the mean of its divisors is an integer number (4475461312).
Almost surely, 217342412553 is an apocalyptic number.
It is an amenable number.
17342412553 is a deficient number, since it is larger than the sum of its proper divisors (559432695).
17342412553 is an equidigital number, since it uses as much as digits as its factorization.
17342412553 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 559432694.
The product of its digits is 100800, while the sum is 37.
The spelling of 17342412553 in words is "seventeen billion, three hundred forty-two million, four hundred twelve thousand, five hundred fifty-three".
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