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17485604051 = 140912409939
BaseRepresentation
bin10000010010001110…
…010010010011010011
31200010121020201102212
4100102032102103103
5241302303312201
612011025102335
71156211116316
oct202216222323
950117221385
1017485604051
117463193143
12347ba879ab
1318587a7a96
14bbc3a897d
156c5149abb
hex4123924d3

17485604051 has 4 divisors (see below), whose sum is σ = 17498015400. Its totient is φ = 17473192704.

The previous prime is 17485603981. The next prime is 17485604077. The reversal of 17485604051 is 15040658471.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15040658471 = 37406504283.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-17485604051 is a prime.

It is a super-2 number, since 2×174856040512 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (17485604351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6203561 + ... + 6206378.

It is an arithmetic number, because the mean of its divisors is an integer number (4374503850).

Almost surely, 217485604051 is an apocalyptic number.

17485604051 is a deficient number, since it is larger than the sum of its proper divisors (12411349).

17485604051 is a wasteful number, since it uses less digits than its factorization.

17485604051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12411348.

The product of its (nonzero) digits is 134400, while the sum is 41.

The spelling of 17485604051 in words is "seventeen billion, four hundred eighty-five million, six hundred four thousand, fifty-one".

Divisors: 1 1409 12409939 17485604051