Base | Representation |
---|---|
bin | 11010001001010101101… |
… | …100110110001000100001 |
3 | 20100202200111021202022220 |
4 | 122021111230312020201 |
5 | 213414202420233103 |
6 | 3453224104221253 |
7 | 243544514165016 |
oct | 32112554661041 |
9 | 6322614252286 |
10 | 1796734149153 |
11 | 632a9964a5a9 |
12 | 25027676a829 |
13 | 10057b75b598 |
14 | 62d68b6170d |
15 | 31b0ce9dc53 |
hex | 1a255b36221 |
1796734149153 has 4 divisors (see below), whose sum is σ = 2395645532208. Its totient is φ = 1197822766100.
The previous prime is 1796734149103. The next prime is 1796734149157. The reversal of 1796734149153 is 3519414376971.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1796734149153 - 214 = 1796734132769 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1796734149157) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 299455691523 + ... + 299455691528.
It is an arithmetic number, because the mean of its divisors is an integer number (598911383052).
Almost surely, 21796734149153 is an apocalyptic number.
It is an amenable number.
1796734149153 is a deficient number, since it is larger than the sum of its proper divisors (598911383055).
1796734149153 is an equidigital number, since it uses as much as digits as its factorization.
1796734149153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 598911383054.
The product of its digits is 17146080, while the sum is 60.
The spelling of 1796734149153 in words is "one trillion, seven hundred ninety-six billion, seven hundred thirty-four million, one hundred forty-nine thousand, one hundred fifty-three".
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