Base | Representation |
---|---|
bin | 1000001111000001100111… |
… | …01101101101001010010001 |
3 | 2101010011001222221020022211 |
4 | 10013200303231231022101 |
5 | 4333142101113130114 |
6 | 102302523523232121 |
7 | 3546202160055031 |
oct | 407406355551221 |
9 | 71104058836284 |
10 | 18108449739409 |
11 | 5851828878667 |
12 | 2045657218641 |
13 | a1480900a403 |
14 | 46864cb278c1 |
15 | 216097d296c4 |
hex | 107833b6d291 |
18108449739409 has 4 divisors (see below), whose sum is σ = 18363498327360. Its totient is φ = 17853401151460.
The previous prime is 18108449739319. The next prime is 18108449739421. The reversal of 18108449739409 is 90493794480181.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 18108449739409 - 219 = 18108449215121 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (18108449739439) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 127524293869 + ... + 127524294010.
It is an arithmetic number, because the mean of its divisors is an integer number (4590874581840).
Almost surely, 218108449739409 is an apocalyptic number.
It is an amenable number.
18108449739409 is a deficient number, since it is larger than the sum of its proper divisors (255048587951).
18108449739409 is an equidigital number, since it uses as much as digits as its factorization.
18108449739409 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 255048587950.
The product of its (nonzero) digits is 62705664, while the sum is 67.
The spelling of 18108449739409 in words is "eighteen trillion, one hundred eight billion, four hundred forty-nine million, seven hundred thirty-nine thousand, four hundred nine".
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