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18134153 = 67270659
BaseRepresentation
bin100010100101…
…1010010001001
31021010022101022
41011023102021
514120243103
61444402225
7310065152
oct105132211
937108338
1018134153
11a266504
1260a6375
1339ac08b
1425a0929
1518d3138
hex114b489

18134153 has 4 divisors (see below), whose sum is σ = 18404880. Its totient is φ = 17863428.

The previous prime is 18134147. The next prime is 18134161. The reversal of 18134153 is 35143181.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35143181 = 311133651.

It is a cyclic number.

It is not a de Polignac number, because 18134153 - 214 = 18117769 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (18134173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135263 + ... + 135396.

It is an arithmetic number, because the mean of its divisors is an integer number (4601220).

Almost surely, 218134153 is an apocalyptic number.

It is an amenable number.

18134153 is a deficient number, since it is larger than the sum of its proper divisors (270727).

18134153 is an equidigital number, since it uses as much as digits as its factorization.

18134153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 270726.

The product of its digits is 1440, while the sum is 26.

The square root of 18134153 is about 4258.4214211372. The cubic root of 18134153 is about 262.7236032777.

Subtracting 18134153 from its reverse (35143181), we obtain a triangular number (17009028 = T5832).

The spelling of 18134153 in words is "eighteen million, one hundred thirty-four thousand, one hundred fifty-three".

Divisors: 1 67 270659 18134153