1941312279553 has 4 divisors (see below), whose sum is σ = 1941323935408. Its totient is φ = 1941300623700.

The previous prime is 1941312279503. The next prime is 1941312279601. The reversal of 1941312279553 is 3559722131491.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1941312279553 - 2¹³ = 1941312271361 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1941312279553.

It is not an unprimeable number, because it can be changed into a prime (1941312279503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5574423 + ... + 5912428.

It is an arithmetic number, because the mean of its divisors is an integer number (485330983852).

Almost surely, 2^{1941312279553} is an apocalyptic number.

It is an amenable number.

1941312279553 is a deficient number, since it is larger than the sum of its proper divisors (11655855).

1941312279553 is a wasteful number, since it uses less digits than its factorization.

1941312279553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11655854.

The product of its digits is 2041200, while the sum is 52.

The spelling of 1941312279553 in words is "one trillion, nine hundred forty-one billion, three hundred twelve million, two hundred seventy-nine thousand, five hundred fifty-three".