Base | Representation |
---|---|
bin | 1011010110111000100… |
… | …0000110110011001011 |
3 | 200122122022212021111020 |
4 | 2311232020012303023 |
5 | 11144102003201313 |
6 | 225345403203523 |
7 | 20045166246012 |
oct | 2655610066313 |
9 | 618568767436 |
10 | 195121147083 |
11 | 75828889855 |
12 | 319958165a3 |
13 | 155275c9665 |
14 | 9630157a79 |
15 | 511ee9d323 |
hex | 2d6e206ccb |
195121147083 has 16 divisors (see below), whose sum is σ = 274746299520. Its totient is φ = 122832982656.
The previous prime is 195121147063. The next prime is 195121147087. The reversal of 195121147083 is 380741121591.
195121147083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 195121147083 - 25 = 195121147051 is a prime.
It is not an unprimeable number, because it can be changed into a prime (195121147087) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5557710 + ... + 5592707.
It is an arithmetic number, because the mean of its divisors is an integer number (17171643720).
Almost surely, 2195121147083 is an apocalyptic number.
195121147083 is a deficient number, since it is larger than the sum of its proper divisors (79625152437).
195121147083 is a wasteful number, since it uses less digits than its factorization.
195121147083 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11150746.
The product of its (nonzero) digits is 60480, while the sum is 42.
The spelling of 195121147083 in words is "one hundred ninety-five billion, one hundred twenty-one million, one hundred forty-seven thousand, eighty-three".
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