Base | Representation |
---|---|
bin | 1011010111100011100… |
… | …1010111001010001001 |
3 | 200200002220211222122110 |
4 | 2311320321113022021 |
5 | 11144434232100210 |
6 | 225415340012533 |
7 | 20052522114120 |
oct | 2657071271211 |
9 | 620086758573 |
10 | 195301831305 |
11 | 75910879559 |
12 | 31a26231149 |
13 | 15555b7cab9 |
14 | 964a14cab7 |
15 | 5130c8e420 |
hex | 2d78e57289 |
195301831305 has 16 divisors (see below), whose sum is σ = 357123348864. Its totient is φ = 89280837120.
The previous prime is 195301831297. The next prime is 195301831321. The reversal of 195301831305 is 503138103591.
It is not a de Polignac number, because 195301831305 - 23 = 195301831297 is a prime.
It is a super-2 number, since 2×1953018313052 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 930008616 + ... + 930008825.
It is an arithmetic number, because the mean of its divisors is an integer number (22320209304).
Almost surely, 2195301831305 is an apocalyptic number.
195301831305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
195301831305 is a deficient number, since it is larger than the sum of its proper divisors (161821517559).
195301831305 is a wasteful number, since it uses less digits than its factorization.
195301831305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1860017456.
The product of its (nonzero) digits is 48600, while the sum is 39.
Adding to 195301831305 its reverse (503138103591), we get a palindrome (698439934896).
The spelling of 195301831305 in words is "one hundred ninety-five billion, three hundred one million, eight hundred thirty-one thousand, three hundred five".
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