Base | Representation |
---|---|
bin | 1011010111100111000… |
… | …1010100000000001001 |
3 | 200200010221110011011201 |
4 | 2311321301110000021 |
5 | 11200002010422231 |
6 | 225421022224201 |
7 | 20053060562341 |
oct | 2657161240011 |
9 | 620127404151 |
10 | 195316498441 |
11 | 75919087159 |
12 | 31a2b125061 |
13 | 15558c16a8c |
14 | 964c089d21 |
15 | 51321da161 |
hex | 2d79c54009 |
195316498441 has 4 divisors (see below), whose sum is σ = 195451480192. Its totient is φ = 195181516692.
The previous prime is 195316498439. The next prime is 195316498469. The reversal of 195316498441 is 144894613591.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 195316498441 - 21 = 195316498439 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (195313498441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67488705 + ... + 67491598.
It is an arithmetic number, because the mean of its divisors is an integer number (48862870048).
Almost surely, 2195316498441 is an apocalyptic number.
It is an amenable number.
195316498441 is a deficient number, since it is larger than the sum of its proper divisors (134981751).
195316498441 is a wasteful number, since it uses less digits than its factorization.
195316498441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 134981750.
The product of its digits is 3732480, while the sum is 55.
The spelling of 195316498441 in words is "one hundred ninety-five billion, three hundred sixteen million, four hundred ninety-eight thousand, four hundred forty-one".
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