Base | Representation |
---|---|
bin | 10010001100101110… |
… | …101100011010010001 |
3 | 1212102211200120211001 |
4 | 102030232230122101 |
5 | 310004433414303 |
6 | 12551005422001 |
7 | 1261146036052 |
oct | 221456543221 |
9 | 55384616731 |
10 | 19540919953 |
11 | 8318381425 |
12 | 395426a901 |
13 | 1ac554c039 |
14 | d35342729 |
15 | 7957d731d |
hex | 48cbac691 |
19540919953 has 4 divisors (see below), whose sum is σ = 19564211520. Its totient is φ = 19517628388.
The previous prime is 19540919941. The next prime is 19540919963. The reversal of 19540919953 is 35991904591.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 19540919953 - 233 = 10950985361 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 19540919894 and 19540919903.
It is not an unprimeable number, because it can be changed into a prime (19540919933) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11644525 + ... + 11646202.
It is an arithmetic number, because the mean of its divisors is an integer number (4891052880).
Almost surely, 219540919953 is an apocalyptic number.
It is an amenable number.
19540919953 is a deficient number, since it is larger than the sum of its proper divisors (23291567).
19540919953 is an equidigital number, since it uses as much as digits as its factorization.
19540919953 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23291566.
The product of its (nonzero) digits is 1968300, while the sum is 55.
The spelling of 19540919953 in words is "nineteen billion, five hundred forty million, nine hundred nineteen thousand, nine hundred fifty-three".
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