Base | Representation |
---|---|
bin | 11100011011111011010… |
… | …000100111010100011001 |
3 | 20220210221201110100011021 |
4 | 130123323100213110121 |
5 | 224004024412321303 |
6 | 4053414252202441 |
7 | 261116114641504 |
oct | 34337320472431 |
9 | 6823851410137 |
10 | 1954130588953 |
11 | 693818856414 |
12 | 276882469421 |
13 | 1123734a992a |
14 | 6a81a98813b |
15 | 35c710a5ebd |
hex | 1c6fb427519 |
1954130588953 has 4 divisors (see below), whose sum is σ = 1954136689360. Its totient is φ = 1954124488548.
The previous prime is 1954130588951. The next prime is 1954130588981. The reversal of 1954130588953 is 3598850314591.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1954130588953 - 21 = 1954130588951 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1954130588891 and 1954130588900.
It is not an unprimeable number, because it can be changed into a prime (1954130588951) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2541423 + ... + 3219796.
It is an arithmetic number, because the mean of its divisors is an integer number (488534172340).
Almost surely, 21954130588953 is an apocalyptic number.
It is an amenable number.
1954130588953 is a deficient number, since it is larger than the sum of its proper divisors (6100407).
1954130588953 is an equidigital number, since it uses as much as digits as its factorization.
1954130588953 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6100406.
The product of its (nonzero) digits is 23328000, while the sum is 61.
The spelling of 1954130588953 in words is "one trillion, nine hundred fifty-four billion, one hundred thirty million, five hundred eighty-eight thousand, nine hundred fifty-three".
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