Base | Representation |
---|---|
bin | 11100011101001001110… |
… | …100010010000010000011 |
3 | 20220221100120110022000020 |
4 | 130131021310102002003 |
5 | 224014224312434140 |
6 | 4054153133024523 |
7 | 261163560346101 |
oct | 34351164220203 |
9 | 6827316408006 |
10 | 1955448561795 |
11 | 694334809973 |
12 | 276b8b925143 |
13 | 112523568411 |
14 | 6a903a26c71 |
15 | 35cebb466d0 |
hex | 1c749d12083 |
1955448561795 has 16 divisors (see below), whose sum is σ = 3163871832480. Its totient is φ = 1031187855104.
The previous prime is 1955448561761. The next prime is 1955448561811. The reversal of 1955448561795 is 5971658445591.
It is a cyclic number.
It is not a de Polignac number, because 1955448561795 - 211 = 1955448559747 is a prime.
It is a super-2 number, since 2×19554485617952 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 732376404 + ... + 732379073.
It is an arithmetic number, because the mean of its divisors is an integer number (197741989530).
Almost surely, 21955448561795 is an apocalyptic number.
1955448561795 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1955448561795 is a deficient number, since it is larger than the sum of its proper divisors (1208423270685).
1955448561795 is a wasteful number, since it uses less digits than its factorization.
1955448561795 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1464755574.
The product of its digits is 272160000, while the sum is 69.
The spelling of 1955448561795 in words is "one trillion, nine hundred fifty-five billion, four hundred forty-eight million, five hundred sixty-one thousand, seven hundred ninety-five".
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