Base | Representation |
---|---|
bin | 10010001101110100… |
… | …001010100000001011 |
3 | 1212111002221210212201 |
4 | 102031310022200023 |
5 | 310024114144042 |
6 | 12552500021031 |
7 | 1261456604653 |
oct | 221564124013 |
9 | 55432853781 |
10 | 19559131147 |
11 | 832768a7a6 |
12 | 395a391777 |
13 | 1ac92571aa |
14 | d37923363 |
15 | 7971d31b7 |
hex | 48dd0a80b |
19559131147 has 4 divisors (see below), whose sum is σ = 19560359056. Its totient is φ = 19557903240.
The previous prime is 19559131133. The next prime is 19559131153. The reversal of 19559131147 is 74113195591.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-19559131147 is a prime.
It is a super-2 number, since 2×195591311472 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 19559131097 and 19559131106.
It is not an unprimeable number, because it can be changed into a prime (19559131117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 589743 + ... + 622024.
It is an arithmetic number, because the mean of its divisors is an integer number (4890089764).
Almost surely, 219559131147 is an apocalyptic number.
19559131147 is a deficient number, since it is larger than the sum of its proper divisors (1227909).
19559131147 is a wasteful number, since it uses less digits than its factorization.
19559131147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1227908.
The product of its digits is 170100, while the sum is 46.
The spelling of 19559131147 in words is "nineteen billion, five hundred fifty-nine million, one hundred thirty-one thousand, one hundred forty-seven".
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