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197032557443 = 1373411434623
BaseRepresentation
bin1011011110000000001…
…1100011101110000011
3200211120112111222120112
42313200003203232003
511212010313314233
6230303203301535
720143436050661
oct2674003435603
9624515458515
10197032557443
1176619818737
123222997a8ab
13157705c69c7
149771d51c31
1551d2bb2048
hex2de00e3b83

197032557443 has 4 divisors (see below), whose sum is σ = 197034129408. Its totient is φ = 197030985480.

The previous prime is 197032557409. The next prime is 197032557467. The reversal of 197032557443 is 344755230791.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 344755230791 = 1301264992491.

It is a cyclic number.

It is not a de Polignac number, because 197032557443 - 210 = 197032556419 is a prime.

It is a super-3 number, since 3×1970325574433 (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 197032557391 and 197032557400.

It is not an unprimeable number, because it can be changed into a prime (197032557493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 579971 + ... + 854652.

It is an arithmetic number, because the mean of its divisors is an integer number (49258532352).

Almost surely, 2197032557443 is an apocalyptic number.

197032557443 is a deficient number, since it is larger than the sum of its proper divisors (1571965).

197032557443 is a wasteful number, since it uses less digits than its factorization.

197032557443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1571964.

The product of its (nonzero) digits is 3175200, while the sum is 50.

The spelling of 197032557443 in words is "one hundred ninety-seven billion, thirty-two million, five hundred fifty-seven thousand, four hundred forty-three".

Divisors: 1 137341 1434623 197032557443