Base | Representation |
---|---|
bin | 10010011100101110… |
… | …000101100011110001 |
3 | 1220010112111102202001 |
4 | 102130232011203301 |
5 | 311032123240043 |
6 | 13033351454001 |
7 | 1300614250546 |
oct | 223456054361 |
9 | 56115442661 |
10 | 19809196273 |
11 | 8445858399 |
12 | 3a0a087301 |
13 | 1b38cc0419 |
14 | d5cc18bcd |
15 | 7ae12b74d |
hex | 49cb858f1 |
19809196273 has 4 divisors (see below), whose sum is σ = 19809594688. Its totient is φ = 19808797860.
The previous prime is 19809196259. The next prime is 19809196291. The reversal of 19809196273 is 37269190891.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 19809196273 - 233 = 11219261681 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (19809196973) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111861 + ... + 228322.
It is an arithmetic number, because the mean of its divisors is an integer number (4952398672).
Almost surely, 219809196273 is an apocalyptic number.
It is an amenable number.
19809196273 is a deficient number, since it is larger than the sum of its proper divisors (398415).
19809196273 is an equidigital number, since it uses as much as digits as its factorization.
19809196273 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 398414.
The product of its (nonzero) digits is 1469664, while the sum is 55.
The spelling of 19809196273 in words is "nineteen billion, eight hundred nine million, one hundred ninety-six thousand, two hundred seventy-three".
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