1983417409633 has 4 divisors (see below), whose sum is σ = 2163728083248. Its totient is φ = 1803106736020.

The previous prime is 1983417409609. The next prime is 1983417409657. The reversal of 1983417409633 is 3369047143891.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (1983417409609) and next prime (1983417409657).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1983417409633 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1983417409333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90155336791 + ... + 90155336812.

It is an arithmetic number, because the mean of its divisors is an integer number (540932020812).

Almost surely, 2^{1983417409633} is an apocalyptic number.

It is an amenable number.

1983417409633 is a deficient number, since it is larger than the sum of its proper divisors (180310673615).

1983417409633 is a wasteful number, since it uses less digits than its factorization.

1983417409633 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 180310673614.

The product of its (nonzero) digits is 11757312, while the sum is 58.

The spelling of 1983417409633 in words is "one trillion, nine hundred eighty-three billion, four hundred seventeen million, four hundred nine thousand, six hundred thirty-three".