1983608949457 has 4 divisors (see below), whose sum is σ = 1983614203120. Its totient is φ = 1983603695796.

The previous prime is 1983608949433. The next prime is 1983608949461. The reversal of 1983608949457 is 7549498063891.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1983608949457 - 2¹¹ = 1983608947409 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1983608949457.

It is not an unprimeable number, because it can be changed into a prime (1983608949557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2012607 + ... + 2831572.

It is an arithmetic number, because the mean of its divisors is an integer number (495903550780).

Almost surely, 2^{1983608949457} is an apocalyptic number.

It is an amenable number.

1983608949457 is a deficient number, since it is larger than the sum of its proper divisors (5253663).

1983608949457 is an equidigital number, since it uses as much as digits as its factorization.

1983608949457 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5253662.

The product of its (nonzero) digits is 470292480, while the sum is 73.

The spelling of 1983608949457 in words is "one trillion, nine hundred eighty-three billion, six hundred eight million, nine hundred forty-nine thousand, four hundred fifty-seven".