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199312433 = 1579126227
BaseRepresentation
bin10111110000101…
…00010000110001
3111220001010020222
423320110100301
5402010444213
631435542425
74640061545
oct1370242061
9456033228
10199312433
11a2563421
12568baa15
13323a6368
141c683a25
1512770808
hexbe14431

199312433 has 4 divisors (see below), whose sum is σ = 199440240. Its totient is φ = 199184628.

The previous prime is 199312417. The next prime is 199312469. The reversal of 199312433 is 334213991.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 199312433 - 24 = 199312417 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 199312393 and 199312402.

It is not an unprimeable number, because it can be changed into a prime (199312483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61535 + ... + 64692.

It is an arithmetic number, because the mean of its divisors is an integer number (49860060).

Almost surely, 2199312433 is an apocalyptic number.

It is an amenable number.

199312433 is a deficient number, since it is larger than the sum of its proper divisors (127807).

199312433 is a wasteful number, since it uses less digits than its factorization.

199312433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 127806.

The product of its digits is 17496, while the sum is 35.

The square root of 199312433 is about 14117.8055306057. The cubic root of 199312433 is about 584.1326255129.

The spelling of 199312433 in words is "one hundred ninety-nine million, three hundred twelve thousand, four hundred thirty-three".

Divisors: 1 1579 126227 199312433