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1993136400739 = 11218191006639
BaseRepresentation
bin11101000000010000001…
…011111110100101100011
321001112122002202212211001
4131000100023332211203
5230123420404310424
64123344554132431
7263666530605421
oct35002013764543
97045562685731
101993136400739
116a93145a0100
12282349421117
13115c4b5a8433
146c67b0bc111
1536ca5658844
hex1d0102fe963

1993136400739 has 12 divisors (see below), whose sum is σ = 2202906727840. Its totient is φ = 1801931432400.

The previous prime is 1993136400733. The next prime is 1993136400769. The reversal of 1993136400739 is 9370046313991.

It is not a de Polignac number, because 1993136400739 - 217 = 1993136269667 is a prime.

It is a super-2 number, since 2×19931364007392 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1993136400739.

It is not an unprimeable number, because it can be changed into a prime (1993136400733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 45481419 + ... + 45525220.

Almost surely, 21993136400739 is an apocalyptic number.

1993136400739 is a deficient number, since it is larger than the sum of its proper divisors (209770327101).

1993136400739 is a wasteful number, since it uses less digits than its factorization.

1993136400739 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 91006842 (or 91006831 counting only the distinct ones).

The product of its (nonzero) digits is 3306744, while the sum is 55.

The spelling of 1993136400739 in words is "one trillion, nine hundred ninety-three billion, one hundred thirty-six million, four hundred thousand, seven hundred thirty-nine".

Divisors: 1 11 121 181 1991 21901 91006639 1001073029 11011803319 16472201659 181194218249 1993136400739