1999003433011 has 4 divisors (see below), whose sum is σ = 2152772927872. Its totient is φ = 1845233938152.

The previous prime is 1999003433003. The next prime is 1999003433083. The reversal of 1999003433011 is 1103343009991.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1999003433011 - 2³ = 1999003433003 is a prime.

It is a super-2 number, since 2×1999003433011² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1999003433311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76884747411 + ... + 76884747436.

It is an arithmetic number, because the mean of its divisors is an integer number (538193231968).

Almost surely, 2^{1999003433011} is an apocalyptic number.

1999003433011 is a deficient number, since it is larger than the sum of its proper divisors (153769494861).

1999003433011 is a wasteful number, since it uses less digits than its factorization.

1999003433011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 153769494860.

The product of its (nonzero) digits is 78732, while the sum is 43.

The spelling of 1999003433011 in words is "one trillion, nine hundred ninety-nine billion, three million, four hundred thirty-three thousand, eleven".