Base | Representation |
---|---|
bin | 11101000101111111101… |
… | …001011010110100111011 |
3 | 21002010112202020002202012 |
4 | 131011333221122310323 |
5 | 230224032121404414 |
6 | 4130244422400135 |
7 | 264305360064422 |
oct | 35057751326473 |
9 | 7063482202665 |
10 | 1999301356859 |
11 | 700998548964 |
12 | 283589b9004b |
13 | 1166c18ab771 |
14 | 6caa3b8a2b9 |
15 | 370169c733e |
hex | 1d17fa5ad3b |
1999301356859 has 4 divisors (see below), whose sum is σ = 2053336528704. Its totient is φ = 1945266185016.
The previous prime is 1999301356849. The next prime is 1999301356903. The reversal of 1999301356859 is 9586531039991.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1999301356859 - 220 = 1999300308283 is a prime.
It is a super-3 number, since 3×19993013568593 (a number of 38 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1999301356849) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27017585867 + ... + 27017585940.
It is an arithmetic number, because the mean of its divisors is an integer number (513334132176).
Almost surely, 21999301356859 is an apocalyptic number.
1999301356859 is a deficient number, since it is larger than the sum of its proper divisors (54035171845).
1999301356859 is an equidigital number, since it uses as much as digits as its factorization.
1999301356859 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54035171844.
The product of its (nonzero) digits is 70858800, while the sum is 68.
The spelling of 1999301356859 in words is "one trillion, nine hundred ninety-nine billion, three hundred one million, three hundred fifty-six thousand, eight hundred fifty-nine".
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