Base | Representation |
---|---|
bin | 1011101000110011100… |
… | …1101000011000111001 |
3 | 201010001122002221020121 |
4 | 2322030321220120321 |
5 | 11233430144212442 |
6 | 231503033253241 |
7 | 20305340321545 |
oct | 2721471503071 |
9 | 633048087217 |
10 | 199932413497 |
11 | 778776a9493 |
12 | 328b8b64221 |
13 | 15b1331706b |
14 | 996912aa25 |
15 | 5302573967 |
hex | 2e8ce68639 |
199932413497 has 8 divisors (see below), whose sum is σ = 202389082560. Its totient is φ = 197476883760.
The previous prime is 199932413449. The next prime is 199932413507. The reversal of 199932413497 is 794314239991.
199932413497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 199932413497 - 215 = 199932380729 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (199932413897) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71004 + ... + 636322.
It is an arithmetic number, because the mean of its divisors is an integer number (25298635320).
Almost surely, 2199932413497 is an apocalyptic number.
It is an amenable number.
199932413497 is a deficient number, since it is larger than the sum of its proper divisors (2456669063).
199932413497 is an equidigital number, since it uses as much as digits as its factorization.
199932413497 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 569663.
The product of its digits is 13226976, while the sum is 61.
The spelling of 199932413497 in words is "one hundred ninety-nine billion, nine hundred thirty-two million, four hundred thirteen thousand, four hundred ninety-seven".
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