2000003114121 has 4 divisors (see below), whose sum is σ = 2666670818832. Its totient is φ = 1333335409412.

The previous prime is 2000003114113. The next prime is 2000003114129. The reversal of 2000003114121 is 1214113000002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (2000003114113) and next prime (2000003114129).

It is a cyclic number.

It is not a de Polignac number, because 2000003114121 - 2³ = 2000003114113 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2000003114121.

It is not an unprimeable number, because it can be changed into a prime (2000003114129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333333852351 + ... + 333333852356.

It is an arithmetic number, because the mean of its divisors is an integer number (666667704708).

Almost surely, 2^{2000003114121} is an apocalyptic number.

It is an amenable number.

2000003114121 is a deficient number, since it is larger than the sum of its proper divisors (666667704711).

2000003114121 is an equidigital number, since it uses as much as digits as its factorization.

2000003114121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 666667704710.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 2000003114121 its reverse (1214113000002), we get a palindrome (3214116114123).

The spelling of 2000003114121 in words is "two trillion, three million, one hundred fourteen thousand, one hundred twenty-one".