Base | Representation |
---|---|
bin | 101101011110011011100110… |
… | …110111011111001101111011 |
3 | 222020011010112021120102011201 |
4 | 231132123212313133031323 |
5 | 202203323300011123003 |
6 | 1545212131301235031 |
7 | 60061522504330204 |
oct | 5536334667371573 |
9 | 866133467512151 |
10 | 200003320411003 |
11 | 587aaa2832927a |
12 | 1a521b97402a77 |
13 | 877a303169715 |
14 | 37562d89d45ab |
15 | 181c82a824b1d |
hex | b5e6e6ddf37b |
200003320411003 has 4 divisors (see below), whose sum is σ = 200008388829888. Its totient is φ = 199998251992120.
The previous prime is 200003320410989. The next prime is 200003320411019. The reversal of 200003320411003 is 300114023300002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200003320411003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (200003320411303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2534150251 + ... + 2534229172.
It is an arithmetic number, because the mean of its divisors is an integer number (50002097207472).
Almost surely, 2200003320411003 is an apocalyptic number.
200003320411003 is a deficient number, since it is larger than the sum of its proper divisors (5068418885).
200003320411003 is an equidigital number, since it uses as much as digits as its factorization.
200003320411003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5068418884.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 200003320411003 its reverse (300114023300002), we get a palindrome (500117343711005).
The spelling of 200003320411003 in words is "two hundred trillion, three billion, three hundred twenty million, four hundred eleven thousand, three".
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