Base | Representation |
---|---|
bin | 1011101001000100100… |
… | …0011011011010001011 |
3 | 201010020120200111021112 |
4 | 2322101020123122023 |
5 | 11234101332320410 |
6 | 231514051000535 |
7 | 20310161601332 |
oct | 2722110333213 |
9 | 633216614245 |
10 | 200003401355 |
11 | 7790378473a |
12 | 3291889914b |
13 | 15b24c40404 |
14 | 9974728d19 |
15 | 53088e7105 |
hex | 2e9121b68b |
200003401355 has 16 divisors (see below), whose sum is σ = 241568374080. Its totient is φ = 158960161152.
The previous prime is 200003401327. The next prime is 200003401363. The reversal of 200003401355 is 553104300002.
It is a cyclic number.
It is not a de Polignac number, because 200003401355 - 26 = 200003401291 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 200003401355.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6961961 + ... + 6990629.
It is an arithmetic number, because the mean of its divisors is an integer number (15098023380).
Almost surely, 2200003401355 is an apocalyptic number.
200003401355 is a deficient number, since it is larger than the sum of its proper divisors (41564972725).
200003401355 is a wasteful number, since it uses less digits than its factorization.
200003401355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37718.
The product of its (nonzero) digits is 1800, while the sum is 23.
Adding to 200003401355 its reverse (553104300002), we get a palindrome (753107701357).
The spelling of 200003401355 in words is "two hundred billion, three million, four hundred one thousand, three hundred fifty-five".
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