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20001130993 = 23869614391
BaseRepresentation
bin10010101000001010…
…010000100111110001
31220121220122201200101
4102220022100213301
5311430242142433
613104405352401
71305434544154
oct225012204761
956556581611
1020001130993
118534131828
123a62408701
131b699b266c
14d7a4dbc9b
157c0de107d
hex4a82909f1

20001130993 has 4 divisors (see below), whose sum is σ = 20870745408. Its totient is φ = 19131516580.

The previous prime is 20001130949. The next prime is 20001130997. The reversal of 20001130993 is 39903110002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20001130993 - 29 = 20001130481 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20001130997) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 434807173 + ... + 434807218.

It is an arithmetic number, because the mean of its divisors is an integer number (5217686352).

Almost surely, 220001130993 is an apocalyptic number.

20001130993 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

20001130993 is a deficient number, since it is larger than the sum of its proper divisors (869614415).

20001130993 is an equidigital number, since it uses as much as digits as its factorization.

20001130993 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 869614414.

The product of its (nonzero) digits is 1458, while the sum is 28.

Adding to 20001130993 its reverse (39903110002), we get a palindrome (59904240995).

The spelling of 20001130993 in words is "twenty billion, one million, one hundred thirty thousand, nine hundred ninety-three".

Divisors: 1 23 869614391 20001130993