Base | Representation |
---|---|
bin | 101101011110100011110010… |
… | …110110100111100111011011 |
3 | 222020011222012221110011221211 |
4 | 231132203302312213213123 |
5 | 202203444301012210233 |
6 | 1545220143455443551 |
7 | 60062253402020254 |
oct | 5536436266474733 |
9 | 866158187404854 |
10 | 200012111444443 |
11 | 58803729672871 |
12 | 1a52382b5265b7 |
13 | 877b0a454335c |
14 | 37568d0371b2b |
15 | 181cb924c55cd |
hex | b5e8f2da79db |
200012111444443 has 4 divisors (see below), whose sum is σ = 200015689342528. Its totient is φ = 200008533546360.
The previous prime is 200012111444429. The next prime is 200012111444459. The reversal of 200012111444443 is 344444111210002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200012111444443 - 237 = 199874672490971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (200012111444543) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1788865188 + ... + 1788976993.
It is an arithmetic number, because the mean of its divisors is an integer number (50003922335632).
Almost surely, 2200012111444443 is an apocalyptic number.
200012111444443 is a deficient number, since it is larger than the sum of its proper divisors (3577898085).
200012111444443 is an equidigital number, since it uses as much as digits as its factorization.
200012111444443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3577898084.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 200012111444443 its reverse (344444111210002), we get a palindrome (544456222654445).
The spelling of 200012111444443 in words is "two hundred trillion, twelve billion, one hundred eleven million, four hundred forty-four thousand, four hundred forty-three".
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