Base | Representation |
---|---|
bin | 101101011110100011111000… |
… | …101110101001111100010001 |
3 | 222020011222110210221100100120 |
4 | 231132203320232221330101 |
5 | 202204000001231120423 |
6 | 1545220201340340453 |
7 | 60062256006631011 |
oct | 5536437056517421 |
9 | 866158423840316 |
10 | 200012210020113 |
11 | 5880377a281167 |
12 | 1a523858544729 |
13 | 877b0bbaa875a |
14 | 37568dd4b1c41 |
15 | 181cb9ae97ee3 |
hex | b5e8f8ba9f11 |
200012210020113 has 16 divisors (see below), whose sum is σ = 273892719405120. Its totient is φ = 129736642925376.
The previous prime is 200012210020111. The next prime is 200012210020159. The reversal of 200012210020113 is 311020012210002.
It is not a de Polignac number, because 200012210020113 - 21 = 200012210020111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 200012210020092 and 200012210020101.
It is not an unprimeable number, because it can be changed into a prime (200012210020111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7510906 + ... + 21364412.
It is an arithmetic number, because the mean of its divisors is an integer number (17118294962820).
Almost surely, 2200012210020113 is an apocalyptic number.
It is an amenable number.
200012210020113 is a deficient number, since it is larger than the sum of its proper divisors (73880509385007).
200012210020113 is a wasteful number, since it uses less digits than its factorization.
200012210020113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13983616.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 200012210020113 its reverse (311020012210002), we get a palindrome (511032222230115).
The spelling of 200012210020113 in words is "two hundred trillion, twelve billion, two hundred ten million, twenty thousand, one hundred thirteen".
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