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20001300331 = 36715448461
BaseRepresentation
bin10010101000001010…
…111001111101101011
31220121220222022222011
4102220022321331223
5311430313102311
613104413140351
71305436150645
oct225012717553
956556868864
1020001300331
118534237a81
123a6248a6b7
131b69a4176c
14d7a543895
157c0e26321
hex4a82b9f6b

20001300331 has 4 divisors (see below), whose sum is σ = 20006752464. Its totient is φ = 19995848200.

The previous prime is 20001300289. The next prime is 20001300391. The reversal of 20001300331 is 13300310002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20001300331 - 29 = 20001299819 is a prime.

It is a super-2 number, since 2×200013003312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20001300391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2720560 + ... + 2727901.

It is an arithmetic number, because the mean of its divisors is an integer number (5001688116).

Almost surely, 220001300331 is an apocalyptic number.

20001300331 is a deficient number, since it is larger than the sum of its proper divisors (5452133).

20001300331 is an equidigital number, since it uses as much as digits as its factorization.

20001300331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5452132.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 20001300331 its reverse (13300310002), we get a palindrome (33301610333).

The spelling of 20001300331 in words is "twenty billion, one million, three hundred thousand, three hundred thirty-one".

Divisors: 1 3671 5448461 20001300331